25b^2+50b+11=-13

Solution for 25b^2+50b+11=-13 equation:

25b^2+50b+11=-13

We move all terms to the left:

25b^2+50b+11-(-13)=0

We add all the numbers together, and all the variables

25b^2+50b+24=0

a = 25; b = 50; c = +24;
Δ = b2-4ac
Δ = 502-4·25·24
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-10}{2*25}=\frac{-60}{50}
=-1+1/5
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+10}{2*25}=\frac{-40}{50}
=-4/5
$